题目内容
计算：(
+
)÷
．
| 1 |
| 2x-1 |
| x |
| 1-2x |
| 1-2x+x2 |
| 1-2x |
原式=（
-
）÷
=
÷
=
•
=
．
| 1 |
| 2x-1 |
| x |
| 2x-1 |
| 1-2x+x2 |
| 1-2x |
=
| 1-x |
| 2x-1 |
| (1-x)2 |
| 1-2x |
=
| 1-x |
| 2x-1 |
| 1-2x |
| (1-x)2 |
=
| 1 |
| x-1 |
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