题目内容
已知x+y=-4,xy=-12,求
+
的值.
| y+1 |
| x+1 |
| x+1 |
| y+1 |
原式=
=
=
∵x+y=-4,xy=-12,
∴原式=
=-
.
| (y+1)2+(x+1)2 |
| (x+1)(y+1) |
=
| x2+y2+2(x+y)+2 |
| xy+x+y+1 |
=
| (x+y)2-2xy+2(x+y)+2 |
| xy+x+y+1 |
∵x+y=-4,xy=-12,
∴原式=
| 16+24-8+2 |
| -12-4+1 |
| 34 |
| 15 |
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