题目内容
(1)分解因式:4a2-3b(4a-3b);
(2)计算:[(x-2y)2+(x-2y)(x+2y)-2x(2x-y)]÷2x.
(2)计算:[(x-2y)2+(x-2y)(x+2y)-2x(2x-y)]÷2x.
(1)原式=4a2-12ab+9b2=(2a-3b)2;
(2)原式=(x2-4xy+4y2+x2-4y2-4x2+2xy)÷2x=(-2x2-2xy)÷2x=-x-y.
(2)原式=(x2-4xy+4y2+x2-4y2-4x2+2xy)÷2x=(-2x2-2xy)÷2x=-x-y.
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