题目内容
设x2-
x+7=0,则x4+7x2+49=( )
| 7 |
| A.7 | B.
| C.-
| D.0 |
∵x4+7x2+49=x2(x2+7)+49
又∵x2-
x+7=0,
∴x2=
x-7,
∴x2+7=
x,
把x2=
x-7和x2+7=
x代入x2(x2+7)+49得:
=(
x-7)
x+49,
=7x2-7
x+49,
=7(x2-
x+7),
=7×0,
=0.
故选D.
又∵x2-
| 7 |
∴x2=
| 7 |
∴x2+7=
| 7 |
把x2=
| 7 |
| 7 |
=(
| 7 |
| 7 |
=7x2-7
| 7 |
=7(x2-
| 7 |
=7×0,
=0.
故选D.
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设x2-
x+7=0,则x4+7x2+49=( )
| 7 |
| A、7 | ||
B、
| ||
C、-
| ||
| D、0 |