题目内容
计算:
(1)
-
;
(2)(1+
)÷
.
(1)
| a2 |
| a+1 |
| 1 |
| a+1 |
(2)(1+
| y-3 |
| y+3 |
| -2y |
| y2-9 |
(1)原式=
=a-1;
(2)原式=
•
=-y+3.
| (a-1)(a+1) |
| a+1 |
=a-1;
(2)原式=
| 2y |
| y+3 |
| (y+3)(y-3) |
| -2y |
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