题目内容
计算
(1)(2x-y)(4x2-y2)(2x+y)
(2)-2(
x-
y)2
(3)(x-3y)(x-
y)
(4)(-
a3x4-
a2x3)÷(-
ax2)
(5)x2-(x+2)(x-2)-(x+2)2
(6)(2x2+x)-[4x2-(3x2-x)]
(1)(2x-y)(4x2-y2)(2x+y)
(2)-2(
| 1 |
| 3 |
| 3 |
| 2 |
(3)(x-3y)(x-
| 1 |
| 2 |
(4)(-
| 1 |
| 5 |
| 9 |
| 10 |
| 3 |
| 5 |
(5)x2-(x+2)(x-2)-(x+2)2
(6)(2x2+x)-[4x2-(3x2-x)]
(1)(2x-y)(4x2-y2)(2x+y),
=(4x2-y2)2,
=16x4-8x2y2+y4.
(2)-2(
x-
y)2,
=-2(
x2-xy+
y2),
=-
x2+2xy-
y2;
(3)(x-3y)(x-
y)=x2-
xy+
y2;
(4)(-
a3x4-
a2x3)÷(-
ax2)=
a2x2+
ax;
(5)x2-(x+2)(x-2)-(x+2)2,
=x2-(x2-4)-(x2+4x+4),
=-x2-4x;
(6)(2x2+x)-[4x2-(3x2-x)],
=2x2+x-4x2+3x2-x,
=x2.
=(4x2-y2)2,
=16x4-8x2y2+y4.
(2)-2(
| 1 |
| 3 |
| 3 |
| 2 |
=-2(
| 1 |
| 9 |
| 9 |
| 4 |
=-
| 2 |
| 9 |
| 9 |
| 2 |
(3)(x-3y)(x-
| 1 |
| 2 |
| 7 |
| 2 |
| 3 |
| 2 |
(4)(-
| 1 |
| 5 |
| 9 |
| 10 |
| 3 |
| 5 |
| 1 |
| 3 |
| 3 |
| 2 |
(5)x2-(x+2)(x-2)-(x+2)2,
=x2-(x2-4)-(x2+4x+4),
=-x2-4x;
(6)(2x2+x)-[4x2-(3x2-x)],
=2x2+x-4x2+3x2-x,
=x2.
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