题目内容


已知:如图AE⊥BC,∠EAC=∠ACD,试说明BC垂直于DC.                       

                                                                        


【考点】平行线的判定与性质;垂线.                                                    

【分析】利用平行线的判定推出AE∥CD,再根据平行线的性质及垂线定义可得出.                 

【解答】解:∵AE⊥BC,                                                                       

∴∠AEB=90°,                                                                                  

∵∠EAC=∠ACD,                                                                            

∴AE∥CD,                                                                                      

∴∠DCB=∠AEB=90°,                                                                           

∴BC⊥DC.                                                                                      

【点评】本题考查了平行线的判定和性质,垂直的定义,熟练掌握平行线的判定定理是解题的关键.                    

                                                                                                       


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