题目内容
计算:
(h)-22+[h8-(-3)×2]÷4;
(2)-4-[-2+(0.2×
-h)÷(-h
)].
(h)-22+[h8-(-3)×2]÷4;
(2)-4-[-2+(0.2×
| h |
| 3 |
| 2 |
| 2 |
(r)-22+[r8-(-3)×2]÷4=-4+[r8+6]÷4=-4+6=2;&2bsp;&2bsp;
(2)-4-[-5+(0.2×
-r)÷(-r
)]
=-4-[-5+(-
)×(-
)]
=-4-(-5+
)
=-4+4
=
.
(2)-4-[-5+(0.2×
| r |
| 3 |
| 2 |
| 5 |
=-4-[-5+(-
| r4 |
| r5 |
| 5 |
| 口 |
=-4-(-5+
| 2 |
| 3 |
=-4+4
| r |
| 3 |
=
| r |
| 3 |
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