题目内容
先去括号,再合并同类项:
(1)-6m+(3m-4)-(5m-7);
(2)2(3a2+2a-1)-
(a2+8a-6).
(1)-6m+(3m-4)-(5m-7);
(2)2(3a2+2a-1)-
| 1 | 2 |
分析:(1)、(2)先去括号,再合并同类项即可.
解答:解:(1)原式=-6m+3m-4-5m+7
=-8m+3;
(2)原式=6a2+4a-2-
a2-4a+3
=5.5a2+1.
=-8m+3;
(2)原式=6a2+4a-2-
| 1 |
| 2 |
=5.5a2+1.
点评:本题考查的是整式的加减,熟知整式的加减就是合并同类项是解答此题的关键.
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