题目内容
化简与计算
(1)计算:
+
;
-
.
(2)先化简再求值
(
-
)÷
,其x=
-4;
÷
,其中a=-5.
(1)计算:
| a2 |
| a-2 |
| 4 |
| 2-a |
| 12 |
| m2-9 |
| 2 |
| m-3 |
(2)先化简再求值
(
| 3x |
| x-2 |
| x |
| x+2 |
| 2x |
| x2-4 |
| 3 |
| a2-4 |
| a2+6a+9 |
| a-2 |
| 2a+6 |
分析:(1)根据分式的加减法则进行计算即可;
(2)先根据分式混合运算的法则把原式进行化简,再把a或x的值代入进行计算即可.
(2)先根据分式混合运算的法则把原式进行化简,再把a或x的值代入进行计算即可.
解答:解:(1)原式=
-
=
=a+2;
原式=
-
=
=
=-
;
(2)原式=
÷
=
×
=x+4,
当x=
-4时,原式=
-4+4=
;
原式=
×
=
,
当a=-5时,原式=
=3.
| a2 |
| a-2 |
| 4 |
| a-2 |
=
| a2-4 |
| a-2 |
=a+2;
原式=
| 12 |
| (m+3)(m-3) |
| 2(m+3) |
| (m+3)(m-3) |
=
| 12-2m-6 |
| (m+3)(m-3) |
=
| 6-2m |
| (m+3)(m-3) |
=-
| 2 |
| (m+3) |
(2)原式=
| 3x(x+2)-x(x-2) |
| (x-2)(x+2) |
| 2x |
| (x+2)(x-2) |
=
| 2x(x+4) |
| (x+2)(x-2) |
| (x+2)(x-2) |
| 2x |
=x+4,
当x=
| 3 |
| 3 |
| 3 |
原式=
| (a+2)(a-2) |
| (a+3)2 |
| 2(a+3) |
| a-2 |
=
| 2(a+2) |
| a+3 |
当a=-5时,原式=
| 2(-5+2) |
| -5+3 |
点评:本题考查的是分式的化简求值,在解答此类问题时要注意通分及约分的灵活应用.
练习册系列答案
相关题目