题目内容

计算:
(1)
2
x
-
5
x2

(2)
a+1
a-1
-
a-1
a+1

(3)
x
y
-
y
x
+
x2+y2
xy

(4)
2
x2-4
-
1
2x-4
(1)原式=
2x
x2
-
5
x2

=
2x-5
x2


(2)原式=
(a+1)2-(a-1)2
(a+1)(a-1)

=
4a
(a-1)(a+1)


(3)原式=
x2-y2+x2+y2
xy

=
2x
y


(4)原式=
4-(x+2)
2(x+2)(x-2)

=-
1
2(x+2)
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