题目内容
化简:
(1)(xy-y2)÷
•
;
(2)
÷
.
(1)(xy-y2)÷
x2-2xy+y2 |
xy |
x-y |
x2 |
(2)
a-1 |
a-2 |
a2-2a+1 |
2a-4 |
(1)原式=y(x-y)•
•
=
;
(2)原式=
•
=
.
xy |
(x-y)2 |
x-y |
x2 |
y2 |
x |
(2)原式=
a-1 |
a-2 |
2(a-2) |
(a-1)2 |
2 |
a-1 |
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