题目内容
先化简(| x |
| x-2 |
| 2x |
| x2-4 |
| x |
| x-2 |
| 2 |
分析:首先化简所求的代数式,在
,2,-2中只有当x=
时,原式有意义,因而把x=
代入化简后的代数式即可求解.
| 2 |
| 2 |
| 2 |
解答:解:原式=
÷
=
•
=
当x=
时,原式=
=
=
-1.
| x(x+2)-2x |
| (x+2)(x-2) |
| x |
| x-2 |
=
| x2 |
| (x+2)(x-2) |
| x-2 |
| x |
=
| x |
| x+2 |
当x=
| 2 |
| ||
|
| ||||
| 2 |
| 2 |
点评:本题考查了代数式得化简求值,确定x的值是解题的关键.
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