题目内容
因式分2x2-2x-1=______.
∵2x2-2x-1=0的解是:x=
,
∴x1=
,x2=
,
∴2x2-2x-1=2(x-
)(x-
);
故答案为:2(x-
)(x-
).
1±
| ||
| 2 |
∴x1=
1+
| ||
| 2 |
1-
| ||
| 2 |
∴2x2-2x-1=2(x-
1+
| ||
| 2 |
1-
| ||
| 2 |
故答案为:2(x-
1+
| ||
| 2 |
1-
| ||
| 2 |
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