题目内容
(1)计算:
×(
-2
);
(2)已知x=
+1,y=
-1,求x2-3xy+y2的值.
2
|
1
|
| 15 |
(2)已知x=
| 2 |
| 2 |
(1)原式=
-2
=
-2
=
-4
;
(2)∵x=
+1,y=
-1,
∴x+y=2
,xy=1,
∴x2-3xy+y2
=(x+y)2-5xy
=(2
)2-5
=8-5
=3.
|
|
=
| 3 |
| 40 |
=
| 3 |
| 10 |
(2)∵x=
| 2 |
| 2 |
∴x+y=2
| 2 |
∴x2-3xy+y2
=(x+y)2-5xy
=(2
| 2 |
=8-5
=3.
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