题目内容
若| a |
| 2 |
| b |
| 3 |
| a+b |
| b |
| x |
| 4 |
| y |
| 3 |
| z |
| 2 |
| x-y+3z |
| x |
分析:根据
=
,可得a=
b,再代入所求分式计算即可;根据
=
=
,易求y=
x,z=
x,再把y、z的值代入所求分式进行计算.
| a |
| 2 |
| b |
| 3 |
| 2 |
| 3 |
| x |
| 4 |
| y |
| 3 |
| z |
| 2 |
| 3 |
| 4 |
| 1 |
| 2 |
解答:解:∵
=
,
∴a=
b,
∴
=
=
;
∵
=
=
,
∴y=
x,z=
x,
∴
=
=
.
故答案是
;
.
| a |
| 2 |
| b |
| 3 |
∴a=
| 2 |
| 3 |
∴
| a+b |
| b |
| ||
| b |
| 5 |
| 3 |
∵
| x |
| 4 |
| y |
| 3 |
| z |
| 2 |
∴y=
| 3 |
| 4 |
| 1 |
| 2 |
∴
| x-y+3z |
| x |
x-
| ||||
| x |
| 7 |
| 4 |
故答案是
| 5 |
| 3 |
| 7 |
| 4 |
点评:本题考查了比例的性质.解题的关键是根据已知条件用出现次数多的字母来表示出现次数少的字母.
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