题目内容
计算:
(1) (-2014)0+(-3)2-
(2)(-2a2b3)4+a8(b4 )3
(3)(x-2y)2-(x+2y)(x-2y) (4)(a+2b+3)(a+2b-3)
(1) (-2014)0+(-3)2-
(3)(x-2y)2-(x+2y)(x-2y) (4)(a+2b+3)(a+2b-3)
(1)6;(2)17a8b12;(3)8y2-4xy;(4)a2+4ab+4b2-9.
试题分析:按照整式乘除相关运算进行计算.
试题解析:(1)(-2014)0+(-3)2-(
(2)(-2a2b3)4+a8(b4)3=16a8b12+ a8b12=17a8b12;
(3)(x-2y)2-(x+2y)(x-2y) =x2-4xy+4y2-(x2-4y2) = x2-4xy+4y2-x2+4y2 =8y2-4xy;
(4)(a+2b+3)(a+2b-3) ="(" a+2b)2-9=a2+4ab+4b2-9.
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