题目内容
设x1,x2是一元二次方程
的两实数根,不解方程,求下列各式的值.
(1)x12·x2+x1·x22;
(2)|x1﹣x2|.
(1)x12·x2+x1·x22;
(2)|x1﹣x2|.
解:由题意知:x1+x2=﹣2,x1x2=﹣
,
(1)x12·x2+x1·x22
=x1x2(x1+x2)
=﹣
×(﹣2)
=3;
(2)(x1﹣x2)2
=(x1+x2)2﹣4x1x2
=(﹣2)2﹣4×(﹣
)
=4+6
=10.
∴|x1﹣x2|=
.
(1)x12·x2+x1·x22
=x1x2(x1+x2)
=﹣
=3;
(2)(x1﹣x2)2
=(x1+x2)2﹣4x1x2
=(﹣2)2﹣4×(﹣
=4+6
=10.
∴|x1﹣x2|=
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