题目内容
如图,已知△ABC中,AE:EB=1:3,BD:DC=2:1,AD与CE相交于F.求
+
的值.
| EF |
| FC |
| AF |
| FD |
作EG∥BC交AD于G,则有
| AE |
| EB |
| 1 |
| 3 |
| AE |
| AB |
| 1 |
| 4 |
EG=
| 1 |
| 4 |
| 1 |
| 2 |
∴
| EF |
| FC |
| EG |
| CD |
| 1 |
| 2 |
作DH∥AB交CE于H,则DH=
| 1 |
| 3 |
∴
| AF |
| FD |
| AE |
| DH |
∴
| EF |
| FC |
| AF |
| FD |
| 1 |
| 2 |
| 3 |
| 2 |
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题目内容
| EF |
| FC |
| AF |
| FD |
| AE |
| EB |
| 1 |
| 3 |
| AE |
| AB |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
| EF |
| FC |
| EG |
| CD |
| 1 |
| 2 |
| 1 |
| 3 |
| AF |
| FD |
| AE |
| DH |
| EF |
| FC |
| AF |
| FD |
| 1 |
| 2 |
| 3 |
| 2 |