题目内容


已知∠AOB=80°,∠AOC=30°,则∠BOC=      .                              


110°50° .                                                                                   

【考点】三角形内角和定理.                                                                  

【专题】分类讨论.                                                                          

【分析】分两种情况进行讨论:①射线OC在∠AOB的外部;②射线OC在∠AOB的内部;从而算出∠AOC的度数.                                                                         

【解答】解:①射线OC在∠AOB的外部,如图1,∠AOC=∠AOB+∠BOC=80°+30°=110°;                    

②射线OC在∠AOB的内部,如图2,∠AOC=∠AOB﹣∠BOC=80°﹣30°=50°.                  

故答案为:110°或50°.                                                                          

                                         

【点评】本题考查了角的计算,在解答此题时要注意应用分类讨论思想进行解答,不要漏解.                 


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