Question

计算：（1）tan30°cot60°+cos²30°-sin²45°tan45°
（2）(

1

2

)-1+(2-

3

)0-2

2

cos60°+

1

2 +1

．

Answer 1

（1）tan30°cot60°+cos²30°-sin²45°tan45°
=

3

3

×

3

3

+（

3

2

）²-（

2

2

）²×1
=

1

3

+

3

4

-

1

2

=

7

12

；

（2）(

1

2

)-1+(2-

3

)0-2

2

cos60°+

1

2 +1

=2+1-2

2

×

1

2

+

2

-1
=2．