题目内容
先化简,再求值:| 1 |
| x+1 |
| 1 |
| x2-1 |
| x2-2x+1 |
| x+1 |
| 2 |
分析:把分子进行因式分解,和分母达到约分的目的,然后代值计算.
解答:解:原式=
-
•
=
-
•
=
-
=
当x=
-1时,原式=1.
| 1 |
| x+1 |
| 1 |
| x2-1 |
| x2-2x+1 |
| x+1 |
=
| 1 |
| x+1 |
| 1 |
| (x-1)(x+1) |
| (x-1)2 |
| x+1 |
=
| 1 |
| x+1 |
| x-1 |
| (x+1)2 |
=
| 2 |
| (x+1)2 |
当x=
| 2 |
点评:此题注意借助因式分解的知识达到约分化简的目的.
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