题目内容
计算：（
+
）÷
| x-2 |
| x+2 |
| 4x |
| x2-4 |
| 1 |
| x2-4 |
（
+
）÷
=
×（x+2）（x-2）+
×（x2-4）
=（x-2）2+4x
=x2-4x+4+4x
=x2+4
| x-2 |
| x+2 |
| 4x |
| x2-4 |
| 1 |
| x2-4 |
=
| x-2 |
| x+2 |
| 4x |
| x2-4 |
=（x-2）2+4x
=x2-4x+4+4x
=x2+4
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