题目内容
化简并求值:
(1)6a2-(2a-1)(3a-2)+(a+2)(a-2),其中a=
.
(2)已知
,求7y(x-3y)2-2(3y-x)3的值.
(1)6a2-(2a-1)(3a-2)+(a+2)(a-2),其中a=
| 1 |
| 3 |
(2)已知
|
(1)原式=6a2-(6a2-4a-3a+2)+a2-4
=6a2-6a2+7a-2+a2-4
=a2+7a-6,
当a=
时,
原式=(
)2+7×
-6=-
;
(2)∵
,
∴原式=7y(x-3y)2+2(x-3y)3=(x-3y)2[7y+2(x-3y)]
=(x-3y)2(2x+y)
=3×1
=3.
=6a2-6a2+7a-2+a2-4
=a2+7a-6,
当a=
| 1 |
| 3 |
原式=(
| 1 |
| 3 |
| 1 |
| 3 |
| 32 |
| 9 |
(2)∵
|
∴原式=7y(x-3y)2+2(x-3y)3=(x-3y)2[7y+2(x-3y)]
=(x-3y)2(2x+y)
=3×1
=3.
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