题目内容
若(x-y)2+k=(x+y)2,则代数式k=
4xy
4xy
.分析:根据题意得到k=(x+y)2-(x-y)2,然后利用完全平方公式展开,再去括号合并即可.
解答:解:∵(x-y)2+k=(x+y)2,
∴k=(x+y)2-(x-y)2
=x2+2xy+y2-(x2-2xy+y2)
=x2+2xy+y2-x2+2xy-y2
=4xy.
故答案为4xy.
∴k=(x+y)2-(x-y)2
=x2+2xy+y2-(x2-2xy+y2)
=x2+2xy+y2-x2+2xy-y2
=4xy.
故答案为4xy.
点评:本题考查了完全平方公式:(a±b)2=a2±2ab+b2.也考查了代数式的变形能力.
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