题目内容
当m=-| 1 |
| 2 |
| m-3 |
| 2m-4 |
| 5 |
| m-2 |
分析:先把括号里式子通分,再把除法转化为乘法,约分化为最简,最后代值计算.
解答:解:原式=
÷
=
×
=
当m=-
时,
原式=
=
.
| m-3 |
| 2(m-2) |
| (m+3)(m-3) |
| m-2 |
| m-3 |
| 2(m-2) |
| m-2 |
| (m+3)(m-3) |
=
| 1 |
| 2(m+3) |
当m=-
| 1 |
| 2 |
原式=
| 1 | ||
2(-
|
| 1 |
| 5 |
点评:本题主要考查分式的化简求值,解题的关键是通分、约分.
练习册系列答案
相关题目