题目内容
先化简,再求值:2b2+(a+b)(a-b)-(a-b)2,其中a=-3,b=
.
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原式=2b2+a2-b2-(a2+b2-2ab)
=2b2+a2-b2-a2-b2+2ab
=2ab,
当a=-3,b=
时,原式=2×(-3)×
=-3.
=2b2+a2-b2-a2-b2+2ab
=2ab,
当a=-3,b=
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