题目内容

计算下列各式: (1)(﹣2a32+(a23﹣2a·a5
(2) 4(a+2)(a+1)﹣7(a+3)(a﹣3)+30(a﹣1);
(3)先化简,再求值:(2a+b)2﹣(3a﹣b)2+5a(a﹣b),其中a=,b=

解:(1)(﹣2a32+(a23﹣2a·a5
=4a6+a6﹣2a6
=3a6
(2)4(a+2)(a+1)﹣7(a+3)(a﹣3)+30(a﹣1),
=4(a2+3a+2)﹣7(a2﹣9)+30a﹣30,
=4a2+12a+8﹣7a2+63+30a﹣30,
=﹣3a2+42a+41;
(3)(2a+b)2﹣(3a﹣b)2+5a(a﹣b),
=4a2+4ab+b2﹣(9a2﹣6ab+b2)+5a2﹣5ab,
=5ab;
a=,b=时,原式=5××=
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