题目内容
(2012•毕节地区)先化简,再求值:
-
÷
,其中x=
.
| 1 |
| x+1 |
| 3-x |
| x2-6x+9 |
| x2+x |
| x-3 |
| 2 |
分析:先算除法,再算乘法.将分式因式分解后约分,然后进行通分,最后代入数值计算.
解答:解:原式=
-
×
=
+
=
+
=
=
.
当x=
时,原式=
=
.
| 1 |
| x+1 |
| 3-x |
| (x-3)2 |
| x-3 |
| x(x+1) |
=
| 1 |
| x+1 |
| 1 |
| x(x+1) |
=
| x |
| x(x+1) |
| 1 |
| x(x+1) |
=
| x+1 |
| x(x+1) |
=
| 1 |
| x |
当x=
| 2 |
| 1 | ||
|
| ||
| 2 |
点评:本题考查了分式的化简求值,熟悉因式分解及分式的除法是解题的关键.
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