题目内容
计算
(1)-15-(-8)+(-11)-12
(2)(-
)×(
-
)×
÷(-
)
(3)(-2)2+4×(-3)2-(-4)2÷(-2)
(4)-23+[(-4)2-(1-32)×3]
(5)-
ab-
a2+
a2-(-
ab)
(6)4x2-[
x-(
x-3)+3x2].
(1)-15-(-8)+(-11)-12
(2)(-
| 7 |
| 2 |
| 1 |
| 6 |
| 1 |
| 2 |
| 3 |
| 14 |
| 1 |
| 2 |
(3)(-2)2+4×(-3)2-(-4)2÷(-2)
(4)-23+[(-4)2-(1-32)×3]
(5)-
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
(6)4x2-[
| 3 |
| 2 |
| 1 |
| 2 |
(1)原式=-15+8-11-12=-30;
(2)原式=-
×(-
)×
×(-2)=-
;
(3)原式=4+36-8=32;
(4)原式=-8+(16+8×3)=-8+40=32;
(5)原式=-
ab-
a2+
a2+
ab=
ab-
a2;
(6)原式=4x2-(
x-
x+3+3x2)=4x2-
x+
x-3-3x2=x2-x-3.
(2)原式=-
| 7 |
| 2 |
| 1 |
| 3 |
| 3 |
| 14 |
| 1 |
| 2 |
(3)原式=4+36-8=32;
(4)原式=-8+(16+8×3)=-8+40=32;
(5)原式=-
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 6 |
(6)原式=4x2-(
| 3 |
| 2 |
| 1 |
| 2 |
| 3 |
| 2 |
| 1 |
| 2 |
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