Question

若|3x+2y﹣4|+27（5x+6y）²=0，则x，y的值分别是（　　）                         

A．                 B．                 C．                   D．

Answer 1

B

【考点】解二元一次方程组；非负数的性质：绝对值；非负数的性质：偶次方．                 

【专题】计算题；一次方程（组）及应用．                                             

【分析】利用非负数的性质列出方程组，求出方程组的解得到x与y的值即可．                 

【解答】解：∵|3x+2y﹣4|+27（5x+6y）²=0，                                         

∴，                                                                              

①×3﹣②得：4x=12，即x=3，                                                                

把x=3代入①得：y=﹣，                                                                      

则方程组的解为，                                                                      

故选B                                                                                                

【点评】此题考查了解二元一次方程组，以及非负数的性质，熟练掌握运算法则是解本题的关键．