题目内容


如图,已知OD平分∠AOB,射线OC在∠AOD内,∠BOC=2∠AOC,∠AOB=114°.求∠COD的度数.               

                                                                             


【考点】角的计算;角平分线的定义.                                                    

【专题】探究型.                                                                              

【分析】根据OD平分∠AOB,射线OC在∠AOD内,∠BOC=2∠AOC,∠AOB=114°,可以求得∠AOC、∠AOD的度数,从而可以求得∠COD的度数.                                                                 

【解答】解:∵OD平分∠AOB,∠AOB=114°,                                             

∴∠AOD=∠BOD==57°.                                                           

∵∠BOC=2∠AOC,∠AOB=114°,                                                         

∴∠AOC=.                                                                     

∴∠COD=∠AOD﹣∠AOC=57°﹣38°=19°.                                            

【点评】本题考查角的计算,解题的关键是找出所求问题需要的条件.                 


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