题目内容

计算:
(1)(-2ab+3a)-(2a-b)+6ab;
(2)(3x2y3)2÷(-
1
3
x4y2)

(3)先化简,再求值:(x+2)2-(x+3)(x-3),其中x=-2.
(1)(-2ab+3a)-(2a-b)+6ab
=-2ab+3a-2a+b+6ab
=4ab+a+b;
(2)(3x2y3)2÷(-
1
3
x4y2)

=9x4y6÷(-
1
3
x4y2)

=-27y4
(3)(x+2)2-(x+3)(x-3)
=x2+4x+4-x2+9
=4x+13
当x=-2时,原式=-8+13=5.
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