题目内容
直接写出结果:
(1)3
+(-1
)=______;
(2)
÷(-1.5)=______;
(3)-4-|-4|=______;
(4)(-2)3-32=______;
(5)(-9)+______=9;
(6)-p2-p2-p2=______;
(7)+(a-2)-2(a-6)=______;
(8)如果x<0,并且x2=256,那么x=______.
(1)3
| 1 |
| 4 |
| 1 |
| 12 |
(2)
| 1 |
| 4 |
(3)-4-|-4|=______;
(4)(-2)3-32=______;
(5)(-9)+______=9;
(6)-p2-p2-p2=______;
(7)+(a-2)-2(a-6)=______;
(8)如果x<0,并且x2=256,那么x=______.
(1)3
+(-1
)=3
-1
=2
(2)
÷(-1.5)=
×(-
)=-
(3)-4-|-4|=-4-4=-8
(4)(-2)3-32=-8-9=-17
(5)∵9-(-9)=18,
∴(-9)+18=9;
(6)-p2-p2-p2=-3p2;
(7)+(a-2)-2(a-6)=a-2-2a+12=-a+10;
(8)∵x2=256,
∴x=±16,
又∵x<0,
∴x=-16.
| 1 |
| 4 |
| 1 |
| 12 |
| 3 |
| 12 |
| 1 |
| 12 |
| 1 |
| 6 |
(2)
| 1 |
| 4 |
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 6 |
(3)-4-|-4|=-4-4=-8
(4)(-2)3-32=-8-9=-17
(5)∵9-(-9)=18,
∴(-9)+18=9;
(6)-p2-p2-p2=-3p2;
(7)+(a-2)-2(a-6)=a-2-2a+12=-a+10;
(8)∵x2=256,
∴x=±16,
又∵x<0,
∴x=-16.
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