题目内容
化简代数式
÷
,并判断当x满足不等式组
时该代数式的符号.
| x2-1 |
| x2+2x |
| x-1 |
| x |
|
| x2-1 |
| x2+2x |
| x-1 |
| x |
=
| x2-1 |
| x2+2x |
| x |
| x-1 |
=
| (x-1)(x+1) |
| x(x+2) |
| x |
| x-1 |
=
| x+1 |
| x+2 |
不等式组
|
解不等式①,得x<-1.
解不等式②,得x>-2.
∴不等式组
|
∴当-2<x<-1时,x+1<0,x+2>0,
∴
| x+1 |
| x+2 |
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