题目内容
计算或化简:
(1)
+
-(
-1)0+(-2)-2-3
;
(2)
•(-4
)÷
;
(3)已知:x=
,求x2-x+1的值.
(1)
| 2 | ||
|
| 27 |
| 3 |
|
(2)
| 1 |
| 3 |
-
|
-
|
| 1 |
| 6 |
|
(3)已知:x=
| 2 | ||
|
(1)原式=
+1+3
-1+
-
=3
+
;
(2)原式=
×(-4)×6×
=-8
=-8x2y;
(3)∵x=
,
∴x=
+1,
∴原式=(
+1)2-(
+1)+1=3+2
+1-
-1+1=4+
.
| 3 |
| 3 |
| 1 |
| 4 |
| 3 |
=3
| 3 |
| 1 |
| 4 |
(2)原式=
| 1 |
| 3 |
-
|
=-8
| x4y2 |
=-8x2y;
(3)∵x=
| 2 | ||
|
∴x=
| 3 |
∴原式=(
| 3 |
| 3 |
| 3 |
| 3 |
| 3 |
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