题目内容
化简：（
-
）÷
，并求x=
时的值．
| x-3 |
| x2-2x-3 |
| x |
| x2-1 |
| 1 |
| x+1 |
| 1 | ||
2-
|
原式=[
-
]÷
=[
-
]•(x+1)=
，
当x=
=2+
时，原式=
=
．
| x-3 |
| (x-3)(x+1) |
| x |
| (x+1)(x-1) |
| 1 |
| x+1 |
| x-1 |
| (x+1)(x-1) |
| x |
| (x+1)(x-1) |
| 1 |
| 1-x |
当x=
| 1 | ||
2-
|
| 3 |
| 1 | ||
-1-
|
1-
| ||
| 2 |
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