题目内容
计算:(1)20070+2﹣2﹣(
)2+2009
(2)(3a2b3)·(﹣2ab4)÷(6a2b3)
(3)(2x2)3﹣6x3(x3+2x2﹣x)
(4)(2a+3b)2﹣(2a﹣b)(2a+b)
(2)(3a2b3)·(﹣2ab4)÷(6a2b3)
(3)(2x2)3﹣6x3(x3+2x2﹣x)
(4)(2a+3b)2﹣(2a﹣b)(2a+b)
解:(1)20070+2﹣2﹣(
)2+2009=1+
﹣
+2009=2010;
(2)(3a2b3)·(﹣2ab4)÷(6a2b3)=﹣6a3b7÷6a2b3=﹣ab4;
(3)(2x2)3﹣6x3(x3+2x2﹣x)=8x6﹣6x6﹣12x5+6x4=2x6﹣12x5+6x4;
(4)(2a+3b)2﹣(2a﹣b)(2a+b)=4a2+12ab+9b2﹣4a2+b2=12ab+10b2.
(2)(3a2b3)·(﹣2ab4)÷(6a2b3)=﹣6a3b7÷6a2b3=﹣ab4;
(3)(2x2)3﹣6x3(x3+2x2﹣x)=8x6﹣6x6﹣12x5+6x4=2x6﹣12x5+6x4;
(4)(2a+3b)2﹣(2a﹣b)(2a+b)=4a2+12ab+9b2﹣4a2+b2=12ab+10b2.
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