题目内容
计算:
(1)(
-
)÷
;
(2)(1+
)•
.
(1)(
| x2-4x+4 |
| x2-4 |
| x |
| x+2 |
| x-1 |
| x+2 |
(2)(1+
| 1 |
| x |
| x2-2x+1 |
| x2-1 |
分析:(1)、(2)根据分式混合运算的法则进行计算即可.
解答:解:(1)原式=
•
=
•
=
;
(2)原式=
•
=
.
| x-2-x |
| x+2 |
| x+2 |
| x-1 |
=
| -2 |
| x+2 |
| x+2 |
| x-1 |
=
| 2 |
| 1-x |
(2)原式=
| x+1 |
| x |
| x-1 |
| x+1 |
=
| x-1 |
| x |
点评:本题考查的是分式的混合运算,在解答此类题目时要注意约分的灵活应用.
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