题目内容
化简下列各题:
(1)2a2-3a+1-a2+6a-7
(2)(5x2-3xy+y2)-2(x2-xy+y2)
(1)2a2-3a+1-a2+6a-7
(2)(5x2-3xy+y2)-2(x2-xy+y2)
分析:(1)直接合并同类项即可;
(2)先去括号,再合并同类项即可.
(2)先去括号,再合并同类项即可.
解答:解:(1)原式=a2+3a-6;
(2)原式=5x2-3xy+y2-2x2+2xy-2y2
=3x2-xy-y2.
(2)原式=5x2-3xy+y2-2x2+2xy-2y2
=3x2-xy-y2.
点评:本题考查的是整式的加减,熟知合并同类项的法则是解答此题的关键.
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