题目内容
计算
①
+3
-
+
②(3
-2
)2-(3
+2
)2.
①
| 8 |
|
| 1 | ||
|
| ||
| 2 |
②(3
| 2 |
| 3 |
| 2 |
| 3 |
分析:(1)先把各二次根式化为最简二次根式得到原式=2
+
-
+
,然后合并同类二次根式;
(2)先根据平方差公式得到原式=(3
-2
+3
+2
)(3
-2
-3
-2
),然后把括号内合并后进行二次根式的乘法运算.
| 2 |
| 3 |
| ||
| 2 |
| ||
| 2 |
(2)先根据平方差公式得到原式=(3
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
解答:解:(1)原式=2
+
-
+
=
+
;
(2)原式=(3
-2
+3
+2
)(3
-2
-3
-2
)
=6
×(-4
)
=-24
.
| 2 |
| 3 |
| ||
| 2 |
| ||
| 2 |
=
3
| ||
| 2 |
3
| ||
| 2 |
(2)原式=(3
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
=6
| 2 |
| 3 |
=-24
| 6 |
点评:本题考查了二次根式的混合运算:先把各二次根式化为最简二次根式,再进行二次根式的乘除运算,然后合并同类二次根式.
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