题目内容
化简求值:(| x2-4 |
| x2-4x+4 |
| x-2 |
| x+2 |
| x |
| x-2 |
分析:先通分,再按四则运算进行即可,最后选择一个使分式的分母不为0的数代入求值.
解答:解:原式=[
-
]×
=
×
-
×
=
-
=
=
,
∵x≠±2,0,
∴x取1,
原式=
=
.
| (x+2)(x-2) |
| (x-2)2 |
| x-2 |
| x+2 |
| x-2 |
| x |
=
| (x+2)(x-2) |
| (x-2)2 |
| x-2 |
| x |
| x-2 |
| x+2 |
| x-2 |
| x |
=
| x+2 |
| x |
| (x-2)2 |
| x(x+2) |
=
| (x+2)2-(x-2)2 |
| x(x+2) |
=
| 8 |
| x+4 |
∵x≠±2,0,
∴x取1,
原式=
| 8 |
| 1+4 |
| 8 |
| 5 |
点评:本题考查了分式的化简求值,是基础知识要熟练掌握.
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