题目内容
化简下列各式
(1)3x2-1-2x-5+3x-x2;
(2)
a2-
ab+
a2+ab-b2;
(3)
x-(2x-
y2)+(-
x+
y2);
(4)2x2-3[2x-2(-x2+2x-1)-4];
(5)
-
.
(1)3x2-1-2x-5+3x-x2;
(2)
| 2 |
| 3 |
| 1 |
| 2 |
| 3 |
| 4 |
(3)
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 2 |
| 1 |
| 3 |
(4)2x2-3[2x-2(-x2+2x-1)-4];
(5)
| 1-2x |
| 3 |
| 3-x |
| 4 |
分析:(1)直接合并同类项即可;
(2)直接合并同类项即可;
(3)先去括号,再合并同类项即可;
(4)先小括号,再去中括号,最后再合并同类项即可;
(5)先通分,再合并即可.
(2)直接合并同类项即可;
(3)先去括号,再合并同类项即可;
(4)先小括号,再去中括号,最后再合并同类项即可;
(5)先通分,再合并即可.
解答:解:(1)原式=2x2+x-6;
(2)原式=
a2+
ab-b2;
(3)原式=
x-2x+
y2-
x+
y2=-3x+y2;
(4)原式=2x2-3(2x+2x2-4x+2-4)=2x2-6x2+6x+6=-4x2+6x+6;
(5)原式=
=-
x-
.
(2)原式=
| 17 |
| 12 |
| 1 |
| 2 |
(3)原式=
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 2 |
| 1 |
| 3 |
(4)原式=2x2-3(2x+2x2-4x+2-4)=2x2-6x2+6x+6=-4x2+6x+6;
(5)原式=
| 4-8x-9+3x |
| 12 |
| 5 |
| 12 |
| 5 |
| 12 |
点评:本题考查了整式的加减,解题的关键是去括号、合并同类项.
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