题目内容
①已知x=2-
,求代数式x2-4x-10的值
②用配方法解方程:2x2-8x-1=0.
| 10 |
②用配方法解方程:2x2-8x-1=0.
①∵x=2-
,
∴x2-4x-10,
=x2-4x+4-14,
=(x-2)2-14,
=(2-
-2)2-14,
=10-14,
=-4,
②2x2-8x-1=0,
x2-4x-
=0,
x2-4x=
,
x2-4x+4=
+4,
(x-2)2=
,
x-2=±
,
x=2±
,
x1=2+
,x2=2-
,
| 10 |
∴x2-4x-10,
=x2-4x+4-14,
=(x-2)2-14,
=(2-
| 10 |
=10-14,
=-4,
②2x2-8x-1=0,
x2-4x-
| 1 |
| 2 |
x2-4x=
| 1 |
| 2 |
x2-4x+4=
| 1 |
| 2 |
(x-2)2=
| 9 |
| 2 |
x-2=±
3
| ||
| 2 |
x=2±
3
| ||
| 2 |
x1=2+
3
| ||
| 2 |
3
| ||
| 2 |
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