题目内容
细心观察下图,认真分析各式,然后解答问题.
(
)2+1=2,S1=
(
)2+1=3,S2=
(
)2+1=4,S3=
(1)请用含n(n是正整数)的等式表示上述变化规律;
(2)推算出OA10的长;
(3)求出S12+S22+S22+…+S102的值.

(
| 1 |
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| 2 |
(
| 2 |
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| 2 |
(
| 3 |
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| 2 |
(1)请用含n(n是正整数)的等式表示上述变化规律;
(2)推算出OA10的长;
(3)求出S12+S22+S22+…+S102的值.
(1)(
)2+1=n+1(1分)
Sn=
(n是正整数)(2分)
(2)∵OA1=
,OA2=
,OA3=
,…
∴OA10=
(3分)
(3)S12+S22+S32+…+S102
=(
)2+(
)2+(
)2+…+(
)2(5分)
=
(1+2+3+…+10)
=
.(6分)
| n |
Sn=
| ||
| 2 |
(2)∵OA1=
| 1 |
| 2 |
| 3 |
∴OA10=
| 10 |
(3)S12+S22+S32+…+S102
=(
| ||
| 2 |
| ||
| 2 |
| ||
| 2 |
| ||
| 2 |
=
| 1 |
| 4 |
=
| 55 |
| 4 |
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