题目内容
如图所示,已知四边形ABCD中,∠ABC=∠ACB,∠ABD=∠ADB,∠ACD=∠ADC。
(1)若∠DAC=2∠BAC,则∠DBC/∠BDC=_________;
(2)当∠DAC=3∠BAC时,求∠DBC/∠BDC的值;
(3)∠DAC=n∠BAC时,∠DBC/∠BDC=____________。
(1)若∠DAC=2∠BAC,则∠DBC/∠BDC=_________;
(2)当∠DAC=3∠BAC时,求∠DBC/∠BDC的值;
(3)∠DAC=n∠BAC时,∠DBC/∠BDC=____________。
解:(1)设∠BAC=x°,则∠DAC=2x°,
∴∠ABC=∠ACB=
,
∠ABD=∠ADB=
,
∠ACD=∠ADC=
,
∴∠DBC=∠ABC-∠ABD,
=
-
,
=x°,
∠BDC=∠ADC-∠ADB,
=
-
,
=
,
∴∠DBC/∠BDC=2;
(2)设∠BAC=x°,则∠DAC=3x°,
∴∠ABC=∠ACB=
,
∠ABD=∠ADB=
,
∠ACD=∠ADC=
,
∴∠DBC=∠ABC-∠ABD,
=
-
,
=
,
∠BDC=∠ADC-∠ADB,
=
-
,
=
,
∴∠DBC/∠BDC=3;
(3)设∠BAC=x°,则∠DAC=nx°,
∴∠ABC=∠ACB=
,
∠ABD=∠ADB=
,
∠ACD=∠ADC=
,
∴∠DBC=∠ABC-∠ABD,
=
-
,
=
,
∠BDC=∠ADC-∠ADB,
=
-
,
=
,
∴∠DBC/∠BDC=n。
∴∠ABC=∠ACB=
∠ABD=∠ADB=
∠ACD=∠ADC=
∴∠DBC=∠ABC-∠ABD,
=
=x°,
∠BDC=∠ADC-∠ADB,
=
=
∴∠DBC/∠BDC=2;
(2)设∠BAC=x°,则∠DAC=3x°,
∴∠ABC=∠ACB=
∠ABD=∠ADB=
∠ACD=∠ADC=
∴∠DBC=∠ABC-∠ABD,
=
=
∠BDC=∠ADC-∠ADB,
=
=
∴∠DBC/∠BDC=3;
(3)设∠BAC=x°,则∠DAC=nx°,
∴∠ABC=∠ACB=
∠ABD=∠ADB=
∠ACD=∠ADC=
∴∠DBC=∠ABC-∠ABD,
=
=
∠BDC=∠ADC-∠ADB,
=
=
∴∠DBC/∠BDC=n。
练习册系列答案
相关题目