题目内容
计算:(1)-10+8÷(-2)3-(-2)2×(-3)
(2)-22-(-1)2005×(
-
)÷
+(-3)2
(3)先化简,再求值:(4m+n)-[1-(m-4n)],其中m=
,n=-1
.
(2)-22-(-1)2005×(
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
(3)先化简,再求值:(4m+n)-[1-(m-4n)],其中m=
| 2 |
| 5 |
| 1 |
| 3 |
(1)-10+8÷(-2)3-(-2)2×(-3)
=-10+8÷(-8)-4×(-3)
=-10-1+12
=1;
(2)-22-(-1)2005×(
-
)÷
+(-3)2
=-4-(-1)×(-
)÷
+9
=-4-1×
×6+9
=-4-1+9
=4;
(3)(4m+n)-[1-(m-4n)]
=4m+n-(1-m+4n)
=4m+n-1+m-4n
=(4+1)m+(1-4)n-1
=5m-3n-1;
将m=
,n=-1
代入上式,得
上式=5×
-3×(-1
)-1
=2+4-1
=5.
=-10+8÷(-8)-4×(-3)
=-10-1+12
=1;
(2)-22-(-1)2005×(
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
=-4-(-1)×(-
| 1 |
| 6 |
| 1 |
| 6 |
=-4-1×
| 1 |
| 6 |
=-4-1+9
=4;
(3)(4m+n)-[1-(m-4n)]
=4m+n-(1-m+4n)
=4m+n-1+m-4n
=(4+1)m+(1-4)n-1
=5m-3n-1;
将m=
| 2 |
| 5 |
| 1 |
| 3 |
上式=5×
| 2 |
| 5 |
| 1 |
| 3 |
=2+4-1
=5.
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