题目内容
已知:x+y+z≠0,a、b、c均不为0,且
=a,
=b,
=c,求
+
+
的值.
| x |
| y+z |
| y |
| z+x |
| z |
| x+y |
| a |
| 1+a |
| b |
| 1+b |
| c |
| 1+c |
先把a=
代入
中得,
=
=
,
同理可得
=
,
=
,
∴
+
+
=
+
+
=1.
答:所求式子的答案是1.
| x |
| y+z |
| a |
| 1+a |
| a |
| 1+a |
| ||
1+
|
| x |
| x+y+z |
同理可得
| b |
| 1+b |
| y |
| x+y+z |
| c |
| 1+c |
| z |
| x+y+z |
∴
| a |
| 1+a |
| b |
| 1+b |
| c |
| 1+c |
| x |
| x+y+z |
| y |
| x+y+z |
| z |
| x+y+z |
答:所求式子的答案是1.
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