题目内容
如图所示,在平面直角坐标系中,求三角形ABO的面积.

如图,C点坐标为(-3,3),
S△ABO=S正方形OECD-S△OAD-S△OBE-S△ABC
=3×3-
×3×2-
×3×1-
×2×1
=9-3-
-1
=
.

S△ABO=S正方形OECD-S△OAD-S△OBE-S△ABC
=3×3-
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=9-3-
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=
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