题目内容
化简求值：(
-
)÷
，其中x=
．
| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| x-4 |
| x |
| 1 | ||
2-
|
(
-
)÷
=[
-
]•
=[
-
]•
=
•
=
•
=
，
∵x=
=2+
，
∴原式=
=
．
| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| x-4 |
| x |
=[
| x+2 |
| x(x -2) |
| x-1 |
| (x-2)2 |
| x |
| x-4 |
=[
| (x+2)(x-2) |
| x(x-2)2 |
| x(x-1) |
| x(x-2)2 |
| x |
| x-4 |
=
| x2-4-x2+x |
| x(x-2)2 |
| x |
| x-4 |
=
| x-4 |
| x(x-2)2 |
| x |
| x-4 |
=
| 1 |
| (x-2)2 |
∵x=
| 1 | ||
2-
|
| 3 |
∴原式=
| 1 | ||
(2+
|
| 1 |
| 3 |
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